Risolvi la seguente espressione

$$\left[ \dfrac{4}{3}:\left( 2+\dfrac{1}{2}\cdot \dfrac{2}{3}\right) -\dfrac{1}{2}:\left( 3-\dfrac{2}{3}\right) +\dfrac{1}{7}\right] \cdot \dfrac{5}{2}-\dfrac{1}{3}:\left( 1+\dfrac{1}{3}\right)=$$

$$\left[ \dfrac{4}{3}:\left( 2+\dfrac{1}{3}\right) -\dfrac{1}{2}:\left( \dfrac{9-2}{3}\right) +\dfrac{1}{7}\right] \cdot \dfrac{5}{2}-\dfrac{1}{3}:\left( \dfrac{3+1}{3}\right)=$$

$$\left[ \dfrac{4}{3}:\left( \dfrac{6+1}{3}\right) -\dfrac{1}{2}:\dfrac{7}{3}+\dfrac{1}{7}\right] \cdot \dfrac{5}{2}-\dfrac{1}{3}\cdot \dfrac{3}{4}=$$

$$\left[ \dfrac{4}{3}\cdot \dfrac{3}{7}-\dfrac{1}{2}\cdot \dfrac{3}{7}+\dfrac{1}{7}\right] \cdot \dfrac{5}{2}-\dfrac{1}{4}=$$

$$\left[ \dfrac{4}{7}-\dfrac{1}{14}+\dfrac{1}{7}\right] \cdot \dfrac{5}{2}-\dfrac{1}{4}$$

$$\left[ \dfrac{8-3+2}{14}\right] \cdot \dfrac{5}{2}-\dfrac{1}{4}=$$

$$\dfrac{7}{14}\cdot \dfrac{5}{2}-\dfrac{1}{4}=$$

$$\dfrac{1}{2}\cdot \dfrac{5}{2}-\dfrac{1}{4}=$$

$$\dfrac{5}{4}-\dfrac{1}{4}=$$

$$\dfrac{4}{4}=$$

$$1$$