$$3-\left\{ \left[ \left( \dfrac{5}{6}+\dfrac{5}{12}\right) :\left( 1+\dfrac{2}{3}+\dfrac{5}{6}\right) +\dfrac{1}{6}:\dfrac{1}{2}+\dfrac{1}{4}\right] \cdot \dfrac{4}{13}+\dfrac{2}{3}\right\} :\left[ \left( \dfrac{3}{8}-\dfrac{12}{33}+\dfrac{3}{22}\right): \dfrac{13}{44} \right]$$

$$3-\left\{ \left[ \left( \dfrac{10+5}{12}\right) :\left( \dfrac{6+4+5}{6}\right) +\dfrac{1}{6}\cdot 2+\dfrac{1}{4}\right] \cdot \dfrac{4}{13}+\dfrac{2}{3}\right\} :\left[ \left( \dfrac{33-32+12}{88}\right) \cdot \dfrac{44}{13}\right] =$$

$$3-\left\{ \left[ \dfrac{15}{12}\cdot \dfrac{6}{15}+\dfrac{1}{3}+\dfrac{1}{4}\right] \cdot \dfrac{4}{13}+\dfrac{2}{3}\right\} :\left[ \dfrac{13}{88}\cdot \dfrac{44}{13}\right]=$$

$$3-\left\{ \left[ \dfrac{1}{2}+\dfrac{1}{3}+\dfrac{1}{4}\right] \cdot \dfrac{4}{13}+\dfrac{2}{3}\right\} \cdot 2=$$

$$3-\left\{ \left[ \dfrac{6+4+3}{12}\right] \cdot \dfrac{4}{13}+\dfrac{2}{3}\right\} \cdot 2=$$

$$3\cdot \left\{ \dfrac{13}{12}\cdot \dfrac{4}{13}+\dfrac{2}{3}\right\}\cdot 2=$$

$$3-\left\{ \dfrac{1}{3}+\dfrac{2}{3}\right\} \cdot 2=$$

$$3-\dfrac{3}{3}\cdot 2=$$

$$3-2=$$

$$1$$