Risolvi la seguente espressione:

$$\dfrac{11}{8}-\dfrac{3}{2}\cdot \left\{ 1-\dfrac{1}{3}\cdot \left[ \dfrac{3}{5}+\dfrac{1}{4}\cdot \left( 1-\dfrac{1}{5}\right) -\left( \dfrac{1}{2}-\dfrac{3}{8}\cdot \dfrac{8}{15}\right) \right] \right\}=$$

$$\dfrac{11}{8}-\dfrac{3}{2}\cdot \left\{ 1-\dfrac{1}{3}\cdot \left[ \dfrac{3}{5}+\dfrac{1}{4}\cdot \left( \dfrac{5-1}{5}\right) -\left( \dfrac{1}{2}-\dfrac{1}{5}\right) \right] \right\}=$$

$$\dfrac{11}{8}-\dfrac{3}{2}\left\{ 1-\dfrac{1}{3}\cdot \left[ \dfrac{3}{5}+\dfrac{1}{4}\cdot \dfrac{4}{5}-\left( \dfrac{5-2}{10}\right) \right] \right\}=$$

$$\dfrac{11}{8}-\dfrac{3}{2}\cdot \left\{ 1-\dfrac{1}{3}\cdot \left[ \dfrac{3}{5}+\dfrac{1}{5}-\dfrac{3}{10}\right] \right\}=$$

$$\dfrac{11}{8}-\dfrac{3}{2}\cdot \left\{ 1-\dfrac{1}{3}\cdot \left[ \dfrac{6+2-3}{10}\right] \right\}$$

$$\dfrac{11}{8}-\dfrac{3}{2}\left\{ 1-\dfrac{1}{3}\cdot \dfrac{5}{10}\right\}=$$

$$\dfrac{11}{8}-\dfrac{3}{2}\left\{ 1-\dfrac{1}{3}\cdot \dfrac{1}{2}\right\}=$$

$$\dfrac{11}{8}-\dfrac{3}{2}\cdot \left\{ 1-\dfrac{1}{6}\right\}=$$

$$\dfrac{11}{8}-\dfrac{3}{2}\cdot \left\{ \dfrac{6-1}{6}\right\}=$$

$$\dfrac{11}{8}-\dfrac{3}{2}\cdot \dfrac{5}{6}=$$

$$\dfrac{11}{8}-\dfrac{5}{4}=$$

$$\dfrac{11-10}{8}=$$

$$\dfrac{1}{8}$$