Risolvi la seguente espressione

$$\left(\frac{6}{5}-\frac{3}{10}\right)\times\left(\frac{4}{6}+\frac{7}{6}+\frac{1}{6}\right)-\left(\frac{7}{3}-\frac{10}{15}\right)\times\frac{48}{45}$$

$$\left(\frac{12-3}{10}\right)\times\frac{12}{6}-\left(\frac{35-10}{15}\right)\times\frac{48}{45}$$

$$\frac{9}{10}\times2-\frac{25}{15}\times\frac{48}{45}=$$

$$\frac{9}{5}-\frac{\cancelto{5}{25}}{\cancelto{3}{15}}\times\frac{48}{45}=$$

$$\frac{9}{5}-\frac{\cancelto{1}{5}}{3}\times\frac{48}{\cancelto{9}{45}}=$$

$$\frac{9}{5}-\frac{1}{\cancelto{1}{3}}\times\frac{\cancelto{16}{48}}{9}=$$

$$\frac{9}{5}-\frac{16}{9}=$$

$$\frac{81-80}{45}=$$

$$\frac{1}{45}$$