Risolvi la seguente espressione:

$$1+\left(4+\frac{1}{3}\right)\times\left(4-\frac{1}{3}\right)\times\left(\frac{10}{13}-\frac{1}{2}\right)\times\frac{6}{77}-\frac{1}{6}=$$

$$1+\left(\frac{12+1}{3}\right)\times\left(\frac{12-1}{3}\right)\times\left(\frac{20-13}{26}\right)\times\frac{6}{77}-\frac{1}{6}=$$

$$1+\frac{13}{3}\times\frac{11}{3}\times\frac{7}{26}\times\frac{6}{77}-\frac{1}{6}=$$

$$1+\frac{13}{26}\times\frac{7}{77}\times\frac{11}{3}\times\frac{6}{3}-\frac{1}{6}=$$

$$1+\frac{1}{2}\times\frac{1}{11}\times\frac{11}{3}\times2-\frac{1}{6}=$$

$$1+\frac{1}{2}\times2\times\frac{1}{3}-\frac{1}{6}=$$

$$1+\frac{1}{3}-\frac{1}{6}=$$

$$\frac{6+2-1}{6}=$$

$$\frac{7}{6}$$